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    Classical Mechanics: Projectile Motion

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    A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 8.80 m/s at an angle of 21.0° below the horizontal. It strikes the ground 3.00 s later.

    (a) How far horizontally from the base of the building does the ball strike the ground?

    (b) Find the height from which the ball was thrown.

    (c) How long does it take the ball to reach a point 10.0 m below the level of launching?

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    Solution Preview

    Resolving the initial velocity into horizontal and vertical components:

    Horizontal component ucosθ = 8.8xcos21O = 8.8x0.93 = 8.22 m/s

    Vertical component usinθ = 8.8xsin21O = 8.8x0.36 = 3.15 m/s

    a) Let the horizontal range be R.

    Horizontal speed of the projectile remains constant (as neglecting friction there is no force ...

    Solution Summary

    The expert uses classical mechanics to examine a projectile motion.