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    Stone is released from rest at top of a vertical cliff: Height of cliff, penetration force

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    Q1. A stone of mass 80 grams is released from rest at the top of a vertical cliff. After falling for 3 seconds, it reaches the ground and penetrates 9 cm into the ground.

    Calculate:

    1. the height of the cliff

    2. the average force resisting the penetration

    (assume gravitational acceleration g=10m/sec2)

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    https://brainmass.com/physics/work/stone-released-rest-top-vertical-cliff-9572

    Solution Preview

    Solution. Assume that the height of the cliff is H(m)and the average force resisting the penetration is F (N). Denote the mass of the stone by m, so m=0.08kg. ...

    Solution Summary

    A stone released from rest on top of a vertical cliff is analyzed. With good explanations and calculations, the problem is solved.

    $2.49

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