Q1. A stone of mass 80 grams is released from rest at the top of a vertical cliff. After falling for 3 seconds, it reaches the ground and penetrates 9 cm into the ground.
1. the height of the cliff
2. the average force resisting the penetration
(assume gravitational acceleration g=10m/sec2)© BrainMass Inc. brainmass.com September 28, 2022, 10:36 pm ad1c9bdddf
Solution. Assume that the height of the cliff is H(m)and the average force resisting the penetration is F (N). Denote the mass of the stone by m, so m=0.08kg. ...
A stone released from rest on top of a vertical cliff is analyzed. With good explanations and calculations, the problem is solved.