Waves on stretched string: Wave velocity and time taken.

Related BrainMass Solutions

• Standing waves on stretched string and resonance.

  (1) The wave velocity is given by c = f* Or f = c* Hence the slope of the graph between f and (1/) gives the speed of the wave on the string. The intercept on y axis gives some frequency.

• Transvers waves: Speed of wave on streatched string.

  The velocity of transverse wave in a stretched string is given by Here T is the tension of the string and  is the mass per unit length.

• Telephone with cans - wavs in a stretched string

  43153 Telephone with cans - waves in a stretched string A brother and sister try to communicate with a string tied between two tin cans.

• Various Practice Problems

  The wave velocity on a string is given by the equation: Where F is the tension in the string and µ is its mass per unit length.

• Heat, harmonics, power, calories, efficiency, velocity, wave

  ___ Answer: Velocity of wave on a stretched string = v = √T/m where T = Tension in the string = 2 N, m = mass per unit length of the string = 0.15/1.25 = 0.12 kg/m v = √(2/0.12) = 4.08 m/s 8.

• Meeting of Two Identical Pulses moving along a String

  Part A The two pulses reflect off the boundaries of the string, and at some later time, they pass through the middle of the string and interfere.

• Standing Waves: Vibration of stretched string and organ pipe

  56881 Standing Waves: Vibration of stretched string and organ pipe A vibrating stretched string has length 38 cm, mass 25 grams and is under a tension of 30 newtons. What is the frequency to the nearest Hz of its 3rd harmonic?

• Time taken by the wave on a stretched string.

  Now the speed of the transverse wave in a stretched string is given by where m is the mass per unit length of the string and is m/R hence hence the time taken by the wave to cover the distance R is given by The time taken by the wave

• Problems on wave motion, beats, standing waves

  The velocity of wave on a string(v), tension in the string(T) and mass per unit length of the string(m) are related as : v = √T/m or T = v2m. In the present case m= 0.005/8 and v=120 m/s. T = (120)2 x 0.005/8 = 9 Newtons 6.