1. The distance-time relationship for a moving object is given by s(t) = kt2 + (6k^2 - 10k)t + 2k, where k is a non-zero constant
a) show that acceleration is constant
2. An object moves so that its velocity, v, is related to its position, s, according to v = (b^2 + 2gs)^1/2, where b and g are constants. Show that the acceleration of the object is constant.
Velocity and accelerationare investigated using functions and derivatives.