Kinetic energy of a body of mass; Vertical motion
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22. a) A 200kg car is traveling 22 m/s. Find the kinetic energy in Joules. b) The same car is lifted vertically upward and then dropped from rest. Find the height from which it is dropped if it strikes the ground at 22 m/s (neglect air resistance).
23. In a movie, a monster climbs to the top of a building 30 m above the ground and hurls a boulder upward with a speed of 25 m/s at an angle of 45° above the horizontal. How far from the base of the building does the boulder land?
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The expert examines the kinetic energy of a body of mass for vertical motion.
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22. a) A 200kg car is traveling 22 m/s. Find the kinetic energy in Joules. b) The same car is lifted vertically upward and then dropped from rest. Find the height from which it is dropped if it strikes the ground at 22 m/s (neglect air resistance).
Solution: Kinetic energy of a body of mass m, travelling with speed v is given by:
KE = ½ mv2
Substituting m = 200 kg, v = 22 m/s we get: KE = ½ x 200 x 222 = 48400 J
b) As the car is dropped from rest, initial velocity u = 0, final velocity v = 22 m/s, acceleration due to gravity = g = 9.8 m/s2. Substituting in the kinematic equation v2 - u2 = 2gs (where s = displacement i.e. height ...
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