An object is thrown horizontally from the top of a building at a height of 32.5 m above the ground, it hits the ground 65m from the base of the building. What is the initial speed? What is the velocity just before it hits the ground?
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First I found the time it ...
This solution uses the equations for the y-direction y=(1/2)at^2 + v(initial)t + y(initial) and the x-direction x = (1/2)at^2 + v(initial)t + x(initial). Calculation, answers and a diagram are included.