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A shop sign weighing 245N is supported by a uniform 155N beam. Find the tension in the guy wire and the horizontal and vertical forces exerted by the hinge on the beam
708N, 580N, -6N
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In the following posting, the final moments of inertia are examined for weighing a stop sign.
Please see the attached.
A shop sign weighing 245N is supported by a uniform 155N beam. Find the tension in the guy wire and the horizontal and vertical forces exerted by the hinge on the beam (708N, 580N, -6N)
The forces acting on the beam are shown.
Resolving tension T in the guy wire resolved in horizontal and vertical directions gives horizontal component T cos 35o to the left and Tsin 35o upwards.
Considering equilibrium in horizontal direction we get
Considering equilibrium in vertical direction we get
Or ------------- (2)
Equating moments (torque) of the forces about hinge point we get
Or T = 406/sin 35o = 708 N
Substituting the value of T in equations (1) and (2) we get
The tires of a car make 85 revolutions as the car reduces its speed uniformly from 90km/h to 60km/h. THE tires have a diameter of .90m
a) What was the angular acceleration of each tire?
Like equations of motion for translational motion we can write ...
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