A ballistic pendulum is a great device for measuring projectile speeds that are relatively large. You launch a small mass m into a large mass M, and it swings up a height h where the two masses stick together. Show that the velocity of the projectile (mass m) is given by v= (m+M)/m) times the square root of 2gh

Solution Summary

With formulas and a diagram, the problem is solved.

A simple way to measure the speed of a bullet is with a ballisticpendulum. This consists of a wooden block mass, M, into which the bullet mass, m, is shot. The block is suspended from cables of length, l, and the impact of the bullet causes it to swing through a maximum angle, A. The initial speed of the bullet is v.
a) How

A pendulum is released from rest at a displacement of .31 meters from its equilibrium position. It is stopped abruptly and uniformly at its equilibrium position and it is observed that a loose bit of metal slides without resistance off the pendulum and falls to the floor .95 meters below.
If the projectile started off with

If a metal ball strikes a pendulum and sticks to it. It will have a relationship for conservation of momentum of m*v = (m + M) *V (m and v are the mass and initial velocity of the projectile, M is the mass of the pendulum with no initial velocity and big V is the combined velocity of the pendulum and projectile).
The conse

A 12.0-g rifle bullet is fired with a speed of 380 m/s into a ballisticpendulum with with mass 6.00 kg, suspended from a cord 70.0 cm long. Compute the vertical height through which the pendulum rises. Compute the initial kinetic energy of the bullet. Compute the kinetic energy of the bullet and pendulum immediately after the b

If an object is thrown upward from 15 meters above ground with an initial velocity of 18 meters per second, then its height h above ground after t seconds after it is thrown is given by
h(t)=-4.9tÂ²+18t+15
Use your calculator to answer the following (round to the nearest hundredth, if necessary):
a) Ske

In a ballisticpendulum an object of mass m is fired with an initial speed v_0 at a pendulum bob. The bob has a mass M, which is suspended by a rod of length L and negligible mass. After the collision, the pendulum and object stick together and swing to a maximum angular displacement theta as shown
a). Find an expression for

A 2.50 g bullet, traveling at a speed of 425 m/s, strikes the wooden block of a ballisticpendulum. The block has a mass of 215 g. (a)What is the speed of the bullet/block combination immediately after the collision. (b)How high does the combination rise above its initial position?

How fast must a 10.5g bullet be traveling when it strikes a ballisticpendulum that consist of a block of wood of mass 3.0kg that is suspended by a cord? The bullet gets embedded in the block. The block rises by .22m after the impact.
a. 143 m/s
b. 595 m/s/s
c. 595 m/s
d. 2.67 m/s

A 7.45g bullet from a 9mm pistol has a velocity of 353m/s. It strikes the 0.725kg block of a ballisticpendulum and passes completely through the block. If the block rises through a distance h=12.1cm, what was the velocity of the bullet as it emerged from the block?