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Optics of Light on a Pool

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Looking for a distance below the pool and the time it takes the ray to travel from the swimming pool to the vertical wall.

See attached for exact instruction and figure.

In the diagram above, a ray from a spotlight strikes the surface of a swimming pool at an angle of 70° to the normal at a distance 4.00m from the pool edge. The index of refraction for water is 1.33.

a. Find the distance below the surface "Y" that the ray strikes the vertical wall.
b. Find the time between when the ray strikes the water and when it strikes the vertical wall.

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Solution Summary

Solution attaches a Word file and PDF to explain the mechanics of light travelling from a swimming pool to a wall.

Solution Preview

Please see the attached file.

We see that:

Also:

According to Snell's law we have:

Thus:

The ...

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