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    Lagrange Multipliers and Forces of Constraint

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    With reference to Figure 2, a small cylinder sits initially on top of a large cylinder of radius a, the latter being attached rigidly to a table. The smaller cylinder has mass m and radius b. A small perturbation sets the small cylinder in motion, causing it to roll down the side of the large cylinder. Assume that the coefficient of static friction u is sufficiently large that there is initially no slippage between the two cylinders. Using the method of Lagrange multipliers find the Lagrange's equations and expressions for the generalized forces of constraint. Analyze their relation with the normal force and the force of static friction. Noticing that as the cylinder rolls down the static friction will eventually not be enough to maintain it rolling without slipping, determine the angle theta for which the cylinder starts slipping.

    See attached file for diagrams.

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    Hi

    Please see the attachment.

    The energy of the motion of the cylinder's center of mass is:

    The energy of the cylinder's rotation about its own center of mass is:

    The potential energy is:

    Thus the general Lagrangian is:

    The first constraint is the fact that the cylinder rolls on the surface of ...

    Solution Summary

    This solution provides step by step calculations using Lagrange multipliers.

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