# Series and Parallel Resistors

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Hi. Actually, this is embarrassing, but my question is simply an algebra question. I know the equation and I know the answer, but I can't remember how to GET the answer. Can someone please walk me through this very simple algebra issue?

Equivalent resistance in a circuit = 26 ohms

R1 and R2 are parallel resistors; R1 = 55 ohms

R1 and R2 are in series with R3, which = 12 ohms.

Find R2.

The equation, as given by my professor, is:

26 = 12 + [1 / (1/55) + (1/R2)]

(Answer = 19 ohms)

I just can remember how to solve for that R.

Thank you!

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R2 is solved with a step-by-step approach.

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See attachment. Don't be embarrassed, I'm glad to help!

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Hi. Actually, this is embarrassing, but my question is simply an algebra question. I know the ...

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