The electrical resistance of a particular electrolytic cell is 5.00 Ohms. A potential difference of 50.0 volts is applied across the cell. If the cell is a copper cell, how much time will be required for 63.54 grams of copper to be deposited on the negative electrode? (Assume the valence of copper is +2).
Current I = 50.0V / 5.00Om = 10 A = 10 C/sec = 10à?6.28à?10^18 ...
The potential difference across a cell is determined. The negative electrodes deposited for valence copper is found.