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Wave properties of particles

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The resolving power of a microscope is proportional to the wavelength used. A resolution of approximately 1.0 x 10-11 m (0.01 nm) would be required in order to "see" an atom. (a) If electrons were used (electron microscope), what minimum kinetic energy would be required for the electrons? (b) If phtons were used, what minimum photon energy would be needed to obtain 1.0 x 10-11 m resolution?

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In an electron microscope we are making use of the wave property of the electron. Here we have to use electrons of wavelength
1.0 x 10-11 m (0.01 nm) to "see the atom".

wave nature of particles is described by the de-Broglie equation

lambda = h/mv

where ...

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