# Wave Dynamics and Water Vapor Pressure

See the attached file.

Equations describing wave dynamics and dispersion are used to deduce the following

1.

A wave of period 10s approaching the shore has a height of 1m in deep

water. Calculate (use ?=1.03×103 kg m-3)

(a) The wave speed and group speed in deep water =

(b) The wave steepness in deep water =

(c) The wave power per metre length of crest in deep water =

(d) The wave power per metre length of crest in water 2.5 m deep =

The super cooling of water into droplets is described for the scenario below

2.

Ice particles and super cooled water droplets exist in the same cloud at a temperature if T = 260 K. The water vapor pressure in the cloud is P h2o = 2.50mb. I have to develop an argument that shows the liquid droplets will tend to evaporate and the ice particles will tend to grow.

https://brainmass.com/physics/power/wave-dynamics-water-vapor-pressure-409317

#### Solution Preview

See attached file.

1.

A wave of period 10s approaching the shore has a height of 1m in deep

water. Calculate (use ?=1.03×103 kg m-3)

(a) The wave speed and group speed in deep water =

(b) The wave steepness in deep water =

(c) The wave power per metre length of crest in deep water =

(d) The wave power per metre length of crest in water 2.5 m deep =

- For deep water:

Wave speed (phase velocity ) is given by (1)

(1)

Where wave period ,

- For deep water group velocity

Wave steepness is given by (2) Ref [1]

(2)

Amplitude ,

Wavelength is obtained from so

(3)

Thus and

Wave steepness,

- In deep water the wave power flux per unit length of wave is given by [2] and equation ...

#### Solution Summary

The solution answers questions regarding wave dynamics and water vapor pressure.