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Wave Dynamics and Water Vapor Pressure

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Equations describing wave dynamics and dispersion are used to deduce the following

1.
A wave of period 10s approaching the shore has a height of 1m in deep
water. Calculate (use ?=1.03×103 kg m-3)
(a) The wave speed and group speed in deep water =
(b) The wave steepness in deep water =
(c) The wave power per metre length of crest in deep water =
(d) The wave power per metre length of crest in water 2.5 m deep =

The super cooling of water into droplets is described for the scenario below

2.
Ice particles and super cooled water droplets exist in the same cloud at a temperature if T = 260 K. The water vapor pressure in the cloud is P h2o = 2.50mb. I have to develop an argument that shows the liquid droplets will tend to evaporate and the ice particles will tend to grow.

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See attached file.

1.
A wave of period 10s approaching the shore has a height of 1m in deep
water. Calculate (use ?=1.03×103 kg m-3)
(a) The wave speed and group speed in deep water =
(b) The wave steepness in deep water =
(c) The wave power per metre length of crest in deep water =
(d) The wave power per metre length of crest in water 2.5 m deep =

- For deep water:
Wave speed (phase velocity ) is given by (1)
(1)
Where wave period ,

- For deep water group velocity
Wave steepness is given by (2) Ref [1]
(2)
Amplitude ,
Wavelength is obtained from so
(3)
Thus and
Wave steepness,

- In deep water the wave power flux per unit length of wave is given by [2] and equation ...

Solution Summary

The solution answers questions regarding wave dynamics and water vapor pressure.

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