power dissipated by the generator
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A generator creates a potential difference of 3.7 volts when cranked at 1 revolution/sec, and the voltage is proportional to the cranking rate. If the generator has an internal resistance of 42 ohms, and is connected across a bulb whose resistance is 51 ohms, then if it is cranked at 2.1 revolutions / sec how much current will flow? How much power will be dissipated by the current? How much power will be dissipated in the bulb?
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Solution Summary
This solution explains how to calculate the power dissipated by a generator in the given question.
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First find out the potential when the generator cranks at 2.1 rev/sec.
voltage is proportional to the cranking rate. so V = kc, where c is the cranking rate.
when c = 1 ...
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