Purchase Solution

Current Electricity: Kirchhoff and Ohms law, DC circuit

Not what you're looking for?

Ask Custom Question

Use Kirchhoff's current law and Ohm's law to determine the current in each of the resistors R4, R5, and R6 in the circuit of Figure 2.31 (see attached file). Vs= 10 V, R1= 20 ohms, R2= 40 ohms, R3= 10 ohms, R4=R5=R6= 15 ohms.

Attachments
Purchase this Solution
Solution Summary

Circuit currents are determined using Kirchhoff and Ohms law. Direct circuits are analyzed.

Solution Preview

Please see the attachment.

The easiest way is to find the total current through the circuit first. For this we have to find the equivalent resistance of the circuit

R2 and R3 are in parallel to each other hence they can be considered as a resistance R' given by

or
Similarly R4, R5 and R6 are in parallel and their equivalent resistance R" ...

Purchase this Solution
Free BrainMass Quizzes
The Moon

Test your knowledge of moon phases and movement.

Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

Basic Physics

This quiz will test your knowledge about basic Physics.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

View More Free Quizzes
Related BrainMass Solutions

  • Kirchhoff's Rules

    The given circuit following Kirchhoff;s rules for circuit resistors are analyzed. The current through each resistors are determined.

  • AC/DC Circuits

    c) In DC and AC circuits use P=IV to make sure have enough power to support all loads. So why in part (a) and (b) for DC need to worry about current limiting resistors and for AC do not? Ohms law is ohms law.

  • Basic electrical circuit engineering

    348312 Current flowing in the series circuit, Power dissipated, DC current through the handset A circuit consists of three resistors in series, with values 200 ohms, 100 ohms and 60 ohms.

  • Relative brightness in a circuit, and using modified Kirchhoff's

    64655 Relative Brightness in a Circuit, and using Modified Kirchhoff Help with questions 8.2 and 8.9.

  • A Series RC circuit is analysed and questions answered

    Thus voltage across R V(R) = 10 V At t = 0, Voltage across R, V(R) can be derived by Ohms law as the product of current (i) flowing through R and its resistance Thus V(R) = i*R Thus on rearrangement for i we get i = V(R)/R = 10/50 = 0.2

  • Electricity Topics: Fields, Resistance, Series and Parallel

    7(d) What would be the power dissipated by the series circuit described in 7(a)? 8(a) A circuit consists of 3 pure resistances of 30 Ohms, 60 Ohms and 80 Ohms in parallel with a 120 V DC supply.

  • DC Series Motor Question

    30571 DC Series Motor Question When operating from a 230 V dc supply, a DC series motor operates at 900 rounds per minute with a line current of 75 Amps. Its armature-circuit resistance is 0.13 Ohms, and its series-field resistance is 0.09 Ohms.

  • Ohm's Law: Resistance and Voltage

    For these questions assume the wire resistance is 0.1 Ohms, the power supply is an ideal 6V voltage source, and the light bulb resistance is 30 Ohms. A. For the circuit below, one such wire is connected directly across the power supply.

  • Resistors - Finding the Current

    Basically, it's a circuit with a 15-V battery and 4 resistors. First you hit R1, which = 11 ohms. Then there are two paths -- path #1 contains R2=7.5 ohms; path #2 contains 2 resistors in series, R3=6.2 ohms and R4 = 12 ohms.

View More Related Solutions