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# Newton's Laws of Motion

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A 2500 lb car has 110 hp available to maintain a speed of 60 mph up a hill. How steep a hill can it climb if wind and rolling resistance forces are 40 lbs.

https://brainmass.com/physics/newtons-second-law/newtons-laws-motion-188648

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Net force down the slope = (2500sinθ + 40) lb

In order to move with a constant speed, the force generated by the car's engine must be equal and opposite i.e. (2500sinθ + 40) up the slope.

Work done per sec by the car (power) = Net force generated by the engine x Velocity

Or 110 x 550 = (2500sinθ + 40) x 88 [ 1 HP = 550 ft lb/sec]

Or (2500sinθ + 40) = 110 x 550/88 = 688

Or sinθ = 0.259 or θ = 15O

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!