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    Newton's Laws of Motion

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    A 2500 lb car has 110 hp available to maintain a speed of 60 mph up a hill. How steep a hill can it climb if wind and rolling resistance forces are 40 lbs.

    © BrainMass Inc. brainmass.com December 24, 2021, 7:25 pm ad1c9bdddf
    https://brainmass.com/physics/newtons-second-law/newtons-laws-motion-188648

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    SOLUTION This solution is FREE courtesy of BrainMass!

    Please refer to the attachment.

    Net force down the slope = (2500sinθ + 40) lb

    In order to move with a constant speed, the force generated by the car's engine must be equal and opposite i.e. (2500sinθ + 40) up the slope.

    Work done per sec by the car (power) = Net force generated by the engine x Velocity

    Or 110 x 550 = (2500sinθ + 40) x 88 [ 1 HP = 550 ft lb/sec]

    Or (2500sinθ + 40) = 110 x 550/88 = 688

    Or sinθ = 0.259 or θ = 15O

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 7:25 pm ad1c9bdddf>
    https://brainmass.com/physics/newtons-second-law/newtons-laws-motion-188648

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