(Please see attachment)
A 2500 lb car has 110 hp available to maintain a speed of 60 mph up a hill. How steep a hill can it climb if wind and rolling resistance forces are 40 lbs.© BrainMass Inc. brainmass.com December 24, 2021, 7:25 pm ad1c9bdddf
SOLUTION This solution is FREE courtesy of BrainMass!
Please refer to the attachment.
Net force down the slope = (2500sinθ + 40) lb
In order to move with a constant speed, the force generated by the car's engine must be equal and opposite i.e. (2500sinθ + 40) up the slope.
Work done per sec by the car (power) = Net force generated by the engine x Velocity
Or 110 x 550 = (2500sinθ + 40) x 88 [ 1 HP = 550 ft lb/sec]
Or (2500sinθ + 40) = 110 x 550/88 = 688
Or sinθ = 0.259 or θ = 15O© BrainMass Inc. brainmass.com December 24, 2021, 7:25 pm ad1c9bdddf>