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Newton's laws of motion

A compact car, mass 735 kg, is moving at 1.00*10^2 km/h toward the east. The driver of the compact car suddenly applies the brakes hard for 2.0 s. As a result, an average force of 5.1*10^3 N is exerted on the car to slow it.

(a) What is the change in momentum, that is the magnitude and direction of the impulse, on the car?

(b) Determine the new momentum of the car.

(c) What is the velocity of the car now?

Solution Preview

a) As per Newton's second law : Applied force = Rate of change of momentum

Or F = d(mv)/dt or Impulse d(mv) = Fdt = -5.1x10^3 x ...

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