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# Gravitational force on the 5kg mass due to another mass; what are accelerations?

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A 5kg mass is 4m away from a 10kg mass. Find the gravitational force on the 5kg mass due to the other mass. What is the force on the 10kg mass due to the 5kg mass? If both masses are free to move, what are their respective accelerations?

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The gravitational force on the 5kg mass due to another mass is determined. The Newton's law of gravitational theory is determined. With calculations and explanations, the problems are solved.

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Solution.(a) By the Newton's law of gravitation we know the gravitational force F is

F=GMm/r^2 (1)

where G=6.672*10^(-11) (Nm^2 Kg^(-2)). So,

F=6.672*10^(-11)*5*10/4^2=2.085*10^(-10) (N).

The gravitational force on ...

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• BSc , Wuhan Univ. China
• MA, Shandong Univ.
###### Recent Feedback
• "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
• "excellent work"
• "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
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