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# Determining Speed After Movement

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A 5.06 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 13.9 N at an angle theta = 18.0° above the horizontal, as shown in the figure. The coefficient of kinetic friction between the block and the floor is 0.06. What is the speed of the block 3.5 s after it starts moving?

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With good diagrams and explanations, along with step by step calculations to determine the speed of block, the problem is solved in an attached Word document.

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Denote the supporting force by N, and denote the gravity by Mg. Denote the friction force by f and denote the force pulling the block by F. The directions of these kinds of forces are shown above. We denote the coefficient of kinetic friction between the block and the floor by .
Now we try to ...

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###### Education
• BSc , Wuhan Univ. China
• MA, Shandong Univ.
###### Recent Feedback
• "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
• "excellent work"
• "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
• "Thank you"
• "Thank you very much for your valuable time and assistance!"

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