Two planes leave simultaneously from the same airport, one flying due north and the other flying due east. The north bound plane is flying 50 miles per hour faster than the east bound plane. After 3 hours the planes are 2,440 miles apart. Find the speed of each plane.
I made a guess at it because I really don't know how to figure out two numbers which add up to a sum, where one number is 50 more than the other and the other is unknown.
Let east bound plane has speed v MPH.
hence speed of north bound plane = v+50
After 3 hours, distances travelled by two planes:
s(N) of north bound plane = (v+50)*3
s(E) of East bound plane = v*3
hence separation between ...
The answer is given step-by-step equationally.