Electronics: Using Voltage
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Instructions: When asked to "Derive an Expression", do so providing proof. In schematics, ground and chassis may be assumed to be common, unless specifically stated otherwise. Unless otherwise specified, assume that Op-Amp supply voltages are.
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Solution: Let us denote the junction node of resistances R1 and R2 as x and the voltage at this node as Vx.
Since the diodes are ideal, the voltage drop across a diode is zero when it is on.
Let us first identify the voltage values and ranges of Vi when the diodes D1 and D2 will be on and off.
For -6 > Vi >= -50, D1 is OFF and D2 is ON.
For +50 >= Vi > 4, D1 is ON and D2 is OFF.
For +4 >= Vi>= -6, both D1 and D2 are OFF.
So, let us determine the output voltage Vo for each of these regions.
1. For -6 > Vi >= -50, D1 is OFF and D2 is ON.
Since D1 is OFF, there is no current through the branch of R2.
Vx = Vo - 6.0
Current flowing through R4 from bottom to top is the ...
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