Purchase Solution

# Circuitry Problems

Not what you're looking for?

1) In the following circuit, all bulbs are identical. The voltage drop across bulb A is 10.0 volts

A) Rank the bulbs in terms of brightness, starting with the brightest.
B) Find the voltage between points 1 and 2. State: "the voltage at point 1 is ________ volts relative to point 2." (In other words, if I use my voltmeter, connecting the black lead at point 2 and the red lead at point 1, what would the voltage reading be?)

2) In the circuit below, the current through the 15-ohm resister is .20 A. Find the voltage drop across the 40-ohm resistor. B) Find the voltage V. C) Find the total current supplied by the battery.

The circuit shown is sometimes called a "bridge" configuration. The current through two of the resistors is indicated. We will call the negative battery terminal our "zero" voltage reference, or "ground".

A) Find the battery voltage. (Hint: what are the voltages drops across the two right-handed resistors?).
B) Find the current through the 3.73-ohm resistor.
C) Find the potential, relative to ground, at point B.
D) Find the potential, relative to ground, at point A. (Hint: you will want to use the voltage at point B to solve this.)
E) Find the current through the 4.0-ohm resistor.
F) Find the total current supplied by the battery.
G) Suppose we replaced the bridge circuit with a single resistor, and that the current through the battery remained the same. What would the value of this "equivalent resistor" be?

##### Solution Summary

This Solution contains over 700 words and calculations to aid you in understanding the Solution to these questions.

##### Solution Preview

Hi,

9.7
(A) This we can answer by considering the current through each bulb. The brightest bulb is A because whatever currents are flowing through the B-C string and the D-E-G string, they both must flow through bulb A. Now the B-C string and the D-E-G string are in parallel, so each has the same voltage. But the D-E-G string has more resistance that the B-C string because it has three bulbs instead of two. So less current flows in the D-E-G string than in the B-C string. Thus the bulbs in the B-C string are brighter than those in the D-E-G string. So the ranking is: A, B=C, D=E=G.

(B) The problem states that the voltage drop across bulb A is 10 Volts, and that all bulbs are identical. This tells us that there are 6 Volts across the B-C and D-E-G strings (16 - 10 = 6). Thus there are 3 Volts across bulb B. So if we call the minus terminal of the battery "ground", then with respect to ground the voltage at ...

##### The Moon

Test your knowledge of moon phases and movement.

##### Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

##### Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

##### Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.