Purchase Solution

# Pendulum's period on the earth to period on a moon: moon's gravity acceleration.

Not what you're looking for?

A simple pendulum, length L, completes 12 oscillations in 30 seconds here on the earth where g= 9.8 nt/kg. The same length pendulum on a certain moon of Jupiter, completes 18 oscillations in 54 seconds.

a.) Find the acceleration of gravity, g1, on that moon.

b.) Find the weight on the surface of that moon, of a person whose weight on the surface of the earth is W=686 nt.

##### Solution Summary

The solution clearly explains the problem in arriving at answers. The pendulum's period on the earth to the period on the moon is determined.

##### Solution Preview

a.) From the equation for a simple pendulum executing simple harmonic motion (SHM), recall that if the length of the pendulum is L and the gravity field is g, the period of the SHM, is given ...

##### Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

##### Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

##### Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

##### The Moon

Test your knowledge of moon phases and movement.

##### Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.