Pendulum's period on the earth to period on a moon: moon's gravity acceleration.
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A simple pendulum, length L, completes 12 oscillations in 30 seconds here on the earth where g= 9.8 nt/kg. The same length pendulum on a certain moon of Jupiter, completes 18 oscillations in 54 seconds.
a.) Find the acceleration of gravity, g1, on that moon.
b.) Find the weight on the surface of that moon, of a person whose weight on the surface of the earth is W=686 nt.
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The solution clearly explains the problem in arriving at answers. The pendulum's period on the earth to the period on the moon is determined.
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a.) From the equation for a simple pendulum executing simple harmonic motion (SHM), recall that if the length of the pendulum is L and the gravity field is g, the period of the SHM, is given ...
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