A metal sphere of radius a is surrounded by a metal shell of inner radius b and outer radius R, as shown in the diagram below. The flux through a spherical Gaussian surface located between a and b is 0.85Q/Eplison_o and the flux through a spherical Gaussian surface just outside R is 1.15Q/Eplison_o.

What is the total charge on the inner sphere? (Express your answer as a multiple of Q. For example, if the total charge is 0.2Q, then input 0.2).
What is the surface charge density of the inner sphere? (Express your answer as a multiple of Q/a2.)

What is the total charge on the inner surface of the outer sphere? (Express your answer as a multiple of Q.)

What is the surface charge density of the inner surface of the outer sphere? (Express your answer as a multiple of Q/b2.)

What is the surface charge density of the outer surface of the outer sphere? (Express your answer as a multiple of Q/R2.)

It shows how to determine total charge and surface charge density given the flux. The solution is detailed and was rated '5/5' by the student who posted the questions originally.

... side face, value of for curved surface will be ... the flux through the closed Gaussian surfaces will be ... As the total charge density on either side of the plane ...

... Thus the total bound charge is: ... P = (1 + αz ) z. This means that there will be bound surface charge only at the surfaces that are parallel to the xy ...

... 13.9 = 0.685E Net flux through the Gaussian surface = 0.685E Total charge enclosed by ... and into and out of the page, calculate the surface charge density of the ...

... problem is symmetrical with respect to the plane x=0, the bound charge surface density is the same on the two faces, and the total 0 charge is the sum of the ...

... ε 0 Mg σ= tan θ q Part 4:Finding the total charge on a plate. Since now we know the surface charge density and the area of the plate we simply conclude that ...

... the inner surface which is + Q and hence the total charge on the ... there is no charge within the box the charge enclosed by any Gaussian surface inside will ...

... area A with one of its flat surfaces outside the ... the Gauss' law to the Gaussian surface as follows ... E.ds = Q/ε_0 .....1) where Q = Total charge enclosed by ...