The electrical field in a particular space is E = (X + 1.2)1 N/C with x in meters. Consider a cylindrical Gaussian surface of radius 16 cm that is coaxial with the x axis. One end of the cylinder is at x = 0. (a) What is the magnitude of the electricflux through the other end of the cylinder at x = 3.2 m? (b) What net charge is enclosed within the cylinder?

Solution Summary

This solution contains over 200 words and calculations to determine the magnitude of the electric flux and net change exists in the cylinder.

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... E.ds = Q/ε0 (1) where E = Electric field intensity on the Gaussian surface, Q = Total charge enclosed by the Gaussian surface. ∫E.ds = E x 2ΠrL. ...

... "Electric flux f emerges from a positive charge and ... i) Now to find the field at a distance r ... shells, consider a concentric spherical Gaussian surface of radius ...

... where E = Electric field on the Gaussian surface, Q = Total charge enclosed by the Gaussian surface (the charge ... but opposite charges on their inner surfaces. ...

... Since the magnitude of the electric field is constant everywhere on the spherical Gaussian surface and is normal to the surface at each point, gauss' law gives ...

... a) Determine the electric fields in the three regions r<= a ... m^2. What are the electric field strengths E1 ... is no field possible in a conductor field between the ...

...Electric field every where within the charged hollow cylinder is zero. b) (please see the attached file). Let us consider as Gaussian surface a cylinder of ...