A uniform boom is at an angle of 45 degrees from the ground. It is held in place by a frictionless pin at ground level. Weight A= 2230 nt is suspended from its upper end and the boom's weight B= 441 nt. A cable from its upper end to ground level makes angle 30 degrees with the ground. See ATTACHMENT for a diagram.
Find T, the tension in the cable and the magnitude of P, the total force exerted on the boom by the frictionless pin.
The boom in equilibrium must satisfy 'net torque = 0' about any axis, and also 'net force = 0'.
To get the tension T, in the cable, since the force P exerted by the pin is not known, choose the pin as the location of the axis, and apply total clockwise torque (cl) = total counter clockwise (ccl) ...