A puck of mass 0.270 kg is tied to a string and allowed to revolve in a circle of radius 1.09 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of 1.24 kg is tied to it (see figure in attached Word file). The suspended mass remains in equilibrium while the puck on the tabletop revolves. What is the speed of the puck?
The suspended mass (m2 = 1.24 kg) shows the tension(T) in the string.
Hence, tension in the string:
T = m2*g = 1.24*9.8 = 12.152 N
This tension will provide the centripetal force to the revolving mass (m1 = 0.27 ...
With good explanations and calculations, the problem is solved.