Purchase Solution

Oscillations: Amplitude and Energy Reduction

Not what you're looking for?

Ask Custom Question

An oscillator with a mass of 420g and a period of 0.800s has an amplitude that decreases by 2.30% during each complete oscillation.

A) If the initial amplitude is 7.00cm, what will be the amplitude after 31.0 oscillations?

B) At what time will the energy be reduced to 65.0% of its initial value?

Purchase this Solution
Solution Summary

This solution solves for an oscillator's amplitude and the time that its energy will be reduced to 65% of its initial value.

Solution Preview

After a the first period the amplitude will be A(1) = A(0)*0.977
After the second period the amplitude will be A(2) = A(1)*0.977 = A(0)*0.977^2
It is easy to see that after N periods, the amplitude will be A(N) = A(1)*0.977^N

In our case, N=31 and A(0)=7cm

Thus, after 31 ...

Purchase this Solution
Free BrainMass Quizzes
Basic Physics

This quiz will test your knowledge about basic Physics.

The Moon

Test your knowledge of moon phases and movement.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

View More Free Quizzes
Related BrainMass Solutions

  • Oscillator and Amplitude

    after 48 oscillations and the time in seconds that the energy will be reduced to 29% of its initial value.

  • Oscillation, Motion and Energy

    What are (a) the motion's frequency (in Hz), (b) the initial potential energy of the block-spring system, (c) the initial kinetic energy, and (d) the motion's amplitude?

  • Spring mass system- constant acceleration or velocity

    Calculate the amplitude and the phase of the oscillations of the spring for 2 situations: a) the elevator moves suddenly and then has a constant velocity v.

  • Waves and oscillations

    301597 Waves and oscillations A sound source sends a sinusoidal sound wave of angular frequency 3000 rad / s and amplitude 12.0 nm through a tube of air. The internal radius of the tube is 2.00 cm.

  • Oscillations: The spring with varying force constant

    yes no No the period in any SHM does not depend on the amplitude and hence on A. 3) Are the oscillations simple harmonic?

  • Physics Questions

    The frequency of the oscillations is f = sqrt(k/m) / (2pi) = sqrt( 490 N/m / 20 kg) / (2pi) = 0.79 Hz (B) For amplitude a = 0.20 m, the total mechanical energy of the oscillations is E = k a^2 / 2 = 9.8 J

  • Oscillations and Equilibrium

    56063 Oscillations and Equilibrium The velocity of a simple harmonic oscillator is given by: v = -9.55sin(21.8t) (mks units) a.) What is its angular frequency? b.) What is the amplitude of the motion in meters to two decimal places?

  • Simple harmonic motion

    It undergoes small-amplitude oscillations if displaced slightly from the equilibrium position at the lowest point. Find an expression for the period of these small amplitude oscillations. Please see the attachment.

  • Harmonic oscillators

    If there is no friction or any other dissipative forces, mechanical energy in the system is constant. Therefore, pushing the system away from its equilibrium point, results in oscillations about the equilibrium indefinitely.

View More Related Solutions