A particle with a charge of 5.5 x 10^-8 C is fixed at the origin. A particle with a charge of -2.3 x 10^-8 is moved from x = 3.5 cm on the x axis to y = 4.3 cm on the y axis. The change in potential energy of the two-particle system is equal to what?
The potential energy (U) of a test charge (qo) placed a distance (r) from the point charge (q) is:
U = k*qo*q/r
- k is the coulomb constant ...
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