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Change in Potential Energy

A particle with a charge of 5.5 x 10^-8 C is fixed at the origin. A particle with a charge of -2.3 x 10^-8 is moved from x = 3.5 cm on the x axis to y = 4.3 cm on the y axis. The change in potential energy of the two-particle system is equal to what?

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The potential energy (U) of a test charge (qo) placed a distance (r) from the point charge (q) is:
U = k*qo*q/r

- k is the coulomb constant ...

Solution Summary

This solution provides an explanation of all the steps that are necessary in solving for the final answer to this physics based question. All the equations and variable which need to be understood to solve this problem are outlined.

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