Purchase Solution

Calculating speed as a function of distance

Not what you're looking for?

Ask Custom Question

The scheme presents two blocks:

The first, Block A, is on a table. Block A is attached to an end of a string. At the end of the table, there is a pulley; the string passes by this pulley, then becomes vertical. At the other end of this string (end of this vertical string) there is Block B. So Block A is attached to Block B by this string. One on the table, the other (B) attached to the string (it is a very classical scheme).

Pulley has radiusR and a moment of inertia I.
The rope doesn't slip over the pulley, and the pulley spins on a frictionless axle.
The coefficient of kinetic friction between the block A and the table is (Mu).
The system is released from rest, and block B descends.
Block A has mass M_A, B has mass M_B.

QUESTION) Use energy methods to calculate the speed of block B as a function of the distance d that it has descended.

Purchase this Solution

Solution Summary

This solution provides notes and steps to explain the problem. It uses conservation of energy calculations to find the final velocity equation.

Solution Preview

Note 1. Distance d is the distance MB descends and also the distance MA slides.
Note 2. At the end of the descent, both blocks are moving with final velocity V and ...

Purchase this Solution

Free BrainMass Quizzes
The Moon

Test your knowledge of moon phases and movement.

Basic Physics

This quiz will test your knowledge about basic Physics.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.