A potter's wheel -- a thick stone disk of radius 0.500 m and mass 100 kg -- is freely rotating at 50.0 rev/min. The potter can stop the wheel in 6.00 s by pressing a wet rag against the rim and exerting a radially inward force of 65.0 N. Find the effective coefficient of kinetic friction between the wheel and the rag.

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The 3 pages solution offers full derivations and explanations regarding the angular motion of a decelerating object.
It shows how to solve it in two ways.

... Calculate: The angular deceleration in rad/s ^2 and rev/min/s. Determine the total angular distance traveled over the 90 s time interval, expressed in both ...

...angular acceleration respectively. Using the third equation we have. 302 = 952 + 2 ï ¡*402. gives ï ¡ = - 10.10 rad/s2. Negative sign is for deceleration, ...

... positive angular acceleration of an adjacent distal segment. (SD) (SD) P Value However, there is some disagreement regarding a source of Torques deceleration...

... e) The tension is greater than the weight of the rock. 10. A wheel, originally rotating at 126 rad/s undergoes a constant angular deceleration of 5.00 rad/s2. ...

...Deceleration = a = Force/Mass = - 863/119 = - 7.25 m/s2. ... If the radius of the car wheels is 28 cm, and the final angular speed of the car wheel is 63 rad/s ...

... Simply new deceleration = -4.8/cos13 = -4.9 (m/s2). ... The angular acceleration, then, is proportional to the product of the force times the lever arm. ...