A slab of copper of thickness b = 1.167 mm is thrust into a parallel plate capacitor of C = 2.00×10-11 F of gap d = 7.0 mm, as shown in the figure (image attached); it is centered exactly halfway between the plates. What is the capacitance after the slab is introduced?
If a charge q = 4.00×10-6 C is maintained on the plates, what is the ratio of the stored energy before to that after the slab is inserted? How much work is done on the slab as it is inserted?
The solution shows how to calculate the capacitance and energy stored after a copper slab inserted to the parallel plate capacitor.