# Force on a current carrying conductor due to magnetic field.

In this problem i am not sure if you can just use the right hand screw rule

The cube is 40 cm on each edge. Four straight segments of wire - ab, bc, cd, and da - form a closed loop that carries a current I = 5 A, in the direction shown. The loop is placed in a uniform magnetic field of magnitude B = 0.020 T in the positive y direction. Determine the magnitude and direction of the magnetic force on each segment.

See attached picture.

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The cube is 40 cm on each edge. Four straight segments of wire - ab, bc, cd, and da - form a closed loop that carries a current I = 5 A, in the direction shown. The loop is placed in a uniform magnetic field of magnitude B = 0.020 T in the positive y direction. Determine the magnitude and direction of the magnetic force on each segment.

Answer:

The force on a current carrying wire due to external magnetic field is given by the formula

( is the angle between L and B)

where L is the length of the wire and the direction of its vector is taken ...

#### Solution Summary

The solution is about magnetic force acting on four segments of a current carrying wire wrapped on a cube along its edges and the phase diagonals due to a uniform magnetic field.