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    Force on a current carrying conductor due to magnetic field.

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    In this problem i am not sure if you can just use the right hand screw rule

    The cube is 40 cm on each edge. Four straight segments of wire - ab, bc, cd, and da - form a closed loop that carries a current I = 5 A, in the direction shown. The loop is placed in a uniform magnetic field of magnitude B = 0.020 T in the positive y direction. Determine the magnitude and direction of the magnetic force on each segment.

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    The cube is 40 cm on each edge. Four straight segments of wire - ab, bc, cd, and da - form a closed loop that carries a current I = 5 A, in the direction shown. The loop is placed in a uniform magnetic field of magnitude B = 0.020 T in the positive y direction. Determine the magnitude and direction of the magnetic force on each segment.

    Answer:

    The force on a current carrying wire due to external magnetic field is given by the formula

    ( is the angle between L and B)
    where L is the length of the wire and the direction of its vector is taken ...

    Solution Summary

    The solution is about magnetic force acting on four segments of a current carrying wire wrapped on a cube along its edges and the phase diagonals due to a uniform magnetic field.

    $2.19

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