Explore BrainMass

Explore BrainMass

    Electron in a magnetic field - period of revolution

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    An electron of energy 10eV is circulating in a plane at right angles to a uniform field of strength 10^-4 Wb/m^2 (1 Gauss). Calculate the radius of the orbit of the electron and its period of revolution.

    © BrainMass Inc. brainmass.com March 6, 2023, 12:44 pm ad1c9bdddf

    Solution Preview

    Energy of the electron E = 10eV

    = 10 x 1.6 x 10^-19 Joule

    = 1.6 x 10^-18 J

    mass m = 9.1 x 10^-31 kg

    Also, E = (1/2)mv^2 ...

    Solution Summary

    The electron in a magnetic field is examined. The period of revolution is determined. Solution with step by step explanations and required equations.