# Electron in a magnetic field - period of revolution

Not what you're looking for? Search our solutions OR ask your own Custom question.

An electron of energy 10eV is circulating in a plane at right angles to a uniform field of strength 10^-4 Wb/m^2 (1 Gauss). Calculate the radius of the orbit of the electron and its period of revolution.

Â© BrainMass Inc. brainmass.com March 6, 2023, 12:44 pm ad1c9bdddfhttps://brainmass.com/physics/electric-magnetic-fields/electron-magnetic-field-period-revolution-6590

#### Solution Preview

Energy of the electron E = 10eV

= 10 x 1.6 x 10^-19 Joule

= 1.6 x 10^-18 J

mass m = 9.1 x 10^-31 kg

Also, E = (1/2)mv^2 ...

#### Solution Summary

The electron in a magnetic field is examined. The period of revolution is determined. Solution with step by step explanations and required equations.

$2.49