Electron in a magnetic field - period of revolution
Not what you're looking for? Search our solutions OR ask your own Custom question.
This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!
An electron of energy 10eV is circulating in a plane at right angles to a uniform field of strength 10^-4 Wb/m^2 (1 Gauss). Calculate the radius of the orbit of the electron and its period of revolution.© BrainMass Inc. brainmass.com March 6, 2023, 12:44 pm ad1c9bdddf
Energy of the electron E = 10eV
= 10 x 1.6 x 10^-19 Joule
= 1.6 x 10^-18 J
mass m = 9.1 x 10^-31 kg
Also, E = (1/2)mv^2 ...
The electron in a magnetic field is examined. The period of revolution is determined. Solution with step by step explanations and required equations.