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Electrical Potential Energy

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Hi. Can someone please tell me if I've gotten the right answer to this problem?

A computer monitor accelerates electrons and directs them to the screen in order to create an image. If the accelerating plates are 1.2 cm apart, and have a potential difference of 25,000 V, what is the magnitude of the uniform electric field between them?

My solution:

E = - delta V / delta s = - 25,000 / 0.012 = -2.1 x 10^6 V/m

Thank you!

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Solution Summary

The electrical potential energy is found. The potential differences are analyzed.

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A computer monitor accelerates electrons and directs them to the screen in order to ...

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