A long straight wire carries a current of 31 A to the right. Next to the wire is a square loop with sides 1.0 m in length, as shown in the figure below. The loop carries a current of 2.7 A in the direction indicated. Calculate the magnitude and direction of the net force acting on the loop.

Okay; so we will start you off. What you are looking at is the application of the Biot-Savart Law, first using the magnetic field of the wire on each section of the loop. That's important. You have to evaluate each section of the loop separately, because the magnetic field from the wire varies with the distance from the wire. I'm adding some enhancements to your drawing. (See diagram.) And please note that your stated information and the information in your drawing do not agree. When you solve this you will have to use whichever numbers are correct.

A long straight wire carries a current of 31 A to the right. Next to the wire is a square loop with sides 1.0 m in length, as shown in the figure below. The loop carries a ...

Solution Summary

This solution provides detailed explanation and formula to help the student understand the calculations that need to be done.

... of current through the fourth conductor, direction of forces...Magnitude of force F3 = (μo/4П) 2I3I/4 = 0.5 x 10 ... For net force on the fourth conductor to be zero ...

... At point P2, the magnitude of the magnetic field due to right conductor = µ0I ... Hence, net magnetic field = 50x10-7-33.33x10-7 = 16.67x10-7 T direction out of ...

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