See attached file.
What will happen in the capacitor circuit in the diagram? Include in your explanation what happens to the charge distribution on the capacitors as well as what happens to the brightness of the bulb. Remember that the capacitors are filled with insulator so charge cannot cross them.
In DC circuit the circuits with capacitance act as open circuits. Therefore, in the given circuit the bulb will not light.
BUT! when you switch on (capacitor charging) or switch off (capacitor discharging), the bulb will light for a ...
With good explanations and calculations, the problem is solved.