electric force between two charges

Related BrainMass Solutions

• Direction and Work Done by Electric Field

  a) The zero electric field point has to lie between the two charges +4 units and +1 unit on the line joining them.

• Electric force between baryon and antibaryon

  of the electric force between two electrons at the same separation.

• The Magnitude and the Direction of an Electric Field

  Force between +6.0 uC and test charge, F2 = (k 6.0*10^-6*q)/(0.02)^2 N Direction of force(repulsion) toward -8.0uC charge along the line joining two charges.

• Location where the net electrostatic force is zero

  However, placing a positive charge in the region between the two charges could produce a net zero electric force. Let us place the +7.40 nC at a distance of x centimeters from the -3.50 nC charge.

• Physics: Electric Field a the Mid-Point of Two Charges

  293032 Physics: Electric Field a the Mid-Point of Two Charges The electric field midway between two equal but opposite point charges is 1870 N/C, and the distance between the charges is 19.2 cm. What is the magnitude of the charge on each?

• Physics: Electric Field, strength, charge, intensity

  Find the electric field intensity at a point P midway between two charges of +2.0 x 10-7C if they are 100cm apart?

• Point Charges and Electric Fields

  43449 Point Charges and Electric Fields Please show all work and diagrams plus equations used to solve problem. Thanks! Two point particles, with charges of q1 and q1 are placed a distance r apart.

• Physics Questions: conductor, insulator, induction, repulsio

  Explain the difference between charging by induction and charging by contact. Include details of how the charging occurs. 3. If two equal charges are separated by a certain distance, the force of repulsion is F.

• Electric force between two uniformly charged solid hemispheres

  Electric force between two charges q1 & q2, separated by r, is given as: F = k *q1*q2/r^2 where, k = 1/(4*pi*epsilon) Hence, for the two charges q1=Q/2 & q2=Q/2, separated by a distance of r=3R/8 - (-3R/8) = 3R/4, electric force can be given as:

• Electric forces vs gravitational forces

  There are two reasons for this: 1) most large objects are neutrally charged and 2) the electric force is both attractive (between opposite charges) and repulsive (between same charges).