Two 1.50 kg masses are 3.00 m apart on a frictionless table. Each has + 5.20 C of charge.

What is the magnitude of the electricforce on one of the masses?
What is the magnitude of the electric force between the spheres?
What is the initial acceleration of the mass if it is released and allowed to move?

Solution Summary

The solution computes the electric force between two charges by Coulomb's law. It also shows how to calculate the initial acceleration of the mass if it is released and allowed to move.

Working with electric forces, field and potentials. ... b) What is the electric potential at position (x,y ... m3 ) is at position (0, 0 y ). What is the force on this ...

... Solution: The electric force of a point charge as a result of the presence ... Let's find the forces one by one ... The force on the test charge +2×10-7 C due to the +1 ...

... There is an electric field E =(2 x 104 N/C) ... Find the force exerted by these charges on a fourth charge... 0.05 2m According to Coulomb's law, the forces by the ...

... finally compares the strength of this force with that ... and how these relate to the forces between them ... What are the electric charges of the baryon and antibaryon ...

... 2) Find the electric field and potential at the point (0.0 ... all the charges are positive, the force is of ... arrows indicate the direction of the forces exerted on ...

... At this angle, the forces are balanced ... Draw a force diagram for the balls B) Calculate Force due to gravity F_gravity C) Calculate electric force F_electric D ...

... Gravitational forces acts upon all the masses while electric forces act only between charged objects. Gravitational force is much weaker than the electrical...

...Force experienced by the ball (charge q) placed in the electric field E is given by qE. Other forces acting of the ball are: weight mg acting downwards and ...

... ball of mass 0.01 kg, carrying a charge of -80.0 µC ... The electric force on the ball has a magnitude of 0.032 N. a.) Draw and label the forces acting on ...