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    Physics: Momentum and Speed

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    Question: A 5.00 g bullet is fired with a velocity of 109.5 m/s toward a 8.35 kg stationary solid block resting on a friction less surface.

    (a) What is the change in momentum of the bullet if it is embedded in the block?

    (b) What is the change in momentum of the bullet if it ricochets in the opposite direction with a speed of 99 m/s?

    (c) In which case does the block end up with a greater speed?

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    Solution Preview

    a) Initial momentum of the bullet = 0.005 x 109.5 = 0.548 kg.m/s

    Initial momentum of the block = 0

    As the bullet gets embedded in the block, the velocity of both will be the same after the collision. Let the common speed be v.

    Momentum of the block + bullet after collision = (8.35+0.005)v

    As per the law of conservation of ...

    Solution Summary

    This solution is comprised of a concise, step by step response which lays out all of the required steps needed for solving for these physics based properties. All calculations are included.