Explore BrainMass
Share

Explore BrainMass

    Mechanics and Arbitrary Vectors

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Show that:
    a. Sum of vectors i and j: epsilon(ijk)delta(ij) =0
    b. Sum of vectors j,k: epsilon(ijk)epsilon(njk) = 2delta (in)
    c Sum of vectors i,j,k: epsilon(ijk)epsilon(ijk) = 6

    Show that:
    Sum of vectors k: epsilon (jk)epsilon (mnk) = delta(im)delta (jn) - delta (in)delta (jm)

    Using the epsilon (ijk) notation and in full explicit detail derive:
    (AxB) . (CxD) = (A . C) (B . D) - (A.D)(B.C)

    Let A be an arbitrary vector and let e be a unit vector in some fixed direction. Show that:
    A = e (A.e) + ex (A x e)

    © BrainMass Inc. brainmass.com October 9, 2019, 6:38 pm ad1c9bdddf
    https://brainmass.com/physics/classical-mechanics/mechanics-arbitrary-vectors-93606

    Attachments

    Solution Summary

    This handwritten solution contains step-by-step vector calculations to prove the vector sum statements in the question set. Brief explanations are included, and all formulas are clearly shown.

    $2.19