Physics of Ski Jump
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A skier starts from rest at the top of a hill. The skier coasts down the hill and up a second hill, as the drawing (attached) illustrates. The crest of the second hill is circular, with a radius of r=36 m. Neglect friction and air resistance. What must be the height H of the first hill so that the skier just loses contract with the snow at the crest of the second hill?
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Word document with calculations included to show how a skier must navigate hills in order to achieve lift at a crest.
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Q. A skier starts from rest at the top of a hill. The skier coasts down the hill and up a second hill, as the drawing illustrates. The crest of the second hill is circular, with a radius of r=36 m. Neglect friction and air resistance. What must be the height H of the first hill so that the skier just loses contract with the snow at the crest of the second hill?
Answer:
Radius of the circular hill r = 36 m.
Height of the first hill H = ?
[When the skier starts, his velocity is zero at the top of the 1st hill, i.e. at point A. ...
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