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A car moving at 25 m/s drives over the top of a hill. The top of the hill forms an arc of a vertical circle 121 meters in diameter.

i) What is the centripetal force holding the car in the circle?

ii) What, therefore, is the normal force between the car's tires and the road?

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Solution Summary

The solution provides a step by step solution. The centripetal force for holding the car in the circle is determined.

Solution Preview

Please see the attachment for a schematic.

a) The forces acting on the car at the top of the hill are as shown in the fig.. Weight mg acts vertically downwards and normal reaction N of the ground acts vertically upwards.
Centripetal ...

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