1. A circuit consists of three elements in series. A source delivers 90 W and one of the passive elements absorbs 20 W. How much power does the third element absorb?
2. Find the Norton equivalent circuit to Figure 1-2.
Please only do problems 3.48, 3.49, 3.51, 3.52, 3.54, 3.57, 3.60, 3.61. OK PLEASE show all equations used, work and PLEASE do not skip steps no matter how minor. I learn by example and need to see everything also including pictures of current flow, directions, picture of how each step progressed, etc..
Please show step by s
See attached file for full problem description. Please solve question number 6 only.
6. Calculate all of the unknown voltages and currents in the above circuit, using either node-voltage, mesh-current, or superposition method. Mark your answers directly on a copy of circuit. In all cases, label the actual direction of curren
Please review the below questions and give fully worked out answers and explainations where appropriate so it can assist in my further understanding of electrical and electronic circuit theory for complex simultaneous equations, mesh analysis, and Kirchoffs Laws.
FIGURE 4 shows an amplifier circuit. Write a short report on the operation and performance of the circuit. In completing the report you should:
- Explain the operation of the circuit and in particular the role of resistors R1 and R2.
- Build the circuit in PSpice and use it to determine:
(i) the quiescent value of Vout
1. The current flowing through a circuit is i(t)= 4t+3 A. How much charge passes through the circuit element between 0 and 2 seconds?
2. Three circuit elements are joined at a node in a circuit. Two amps are flowing into the node from one element, and seven amps are leaving the node and flowing into the element two. How many
Please give a full and simplified answer to all parts of question 6 to aid me with revision.
When a force F is applied across the face of the crystal, the current is generated. The interconnecting cable can be represented by a lumped capacitance CC. The input resistance of the amplifier, RL, acts as a load to the