Please show all work and show all equations used and diagrams, etc. etc. so I understand completely please.
1) A particle with charge 5.5*10^-8C is fixed at the origin. A particle with a charge -2.3*10-8C charge is moved from X=3.5cm on the x axis to y=3.5cm on the y axis. The change in PE of the two charge system is:
2) Three particles lie on the x axis: particle 1, with a charge of 1*10^-8C is at 1cm, particle 2, with charge 2*10^-8C is at x=2cm, and particle 3 with charge -3*10^-8C is at x=3cm. The PE of this arrangement, relative to the PE for infinite separation is:
3) Two identical particles each with charge q are placed on the x axis. One at the origin and the other at x=5cm. A third particle with charge -q is placed on the x axis so the PE of the three particle system is the same as the PE at infinite separation. Its x coordinate is:© BrainMass Inc. brainmass.com March 4, 2021, 6:24 pm ad1c9bdddf
This solution is provided in two attached .jpg files. It includes detailed, step-by-step equations for solving the problems, including diagrams to enhance understanding of the problem.