Electrostatic repulsion
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A certain charge Q is divided into two parts q and Q-q. How the charges Q and q must be related so that when q and (Q-q) placed at a certain distance apart experience maximum electrostatic repulsion.
© BrainMass Inc. brainmass.com December 24, 2021, 4:43 pm ad1c9bdddfhttps://brainmass.com/physics/charge/electrostatic-repulsion-maximums-4061
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Ans. The electrostatic force of repulsion between the charges q and (Q-q) at separation r is given by,
F = q(Q-q)/4peo r^2
= (qq-q^2)/4peo r^2
If F is maximum, then
dF/dq = 0
That is
(Q-2q)/4peor^2 = 0
As 1/4peor^2 is constant,
Q-2q = 0
Or Q = 2q
Please see the word attachment for the well formatted answer.
© BrainMass Inc. brainmass.com December 24, 2021, 4:43 pm ad1c9bdddf>https://brainmass.com/physics/charge/electrostatic-repulsion-maximums-4061