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electrostatic repulsion

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1. Consider a conducting ring made of thin wire wheel: d is the diameter of the wire and D is the diameter of the ring (D>>d).

A charge Q placed on the ring is just enough to cause the ring to break apart due to electrostatic repulsion.

All linear dimensions are doubled (multiplied by 2); what is the new charge required to break this new ring?

© BrainMass Inc. brainmass.com September 24, 2018, 9:43 am ad1c9bdddf - https://brainmass.com/physics/charge/charge-required-break-ring-due-electrostatic-repulsion-165237

Solution Summary

It finds the charge required to break the ring due to electrostatic repulsion.

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