Explore BrainMass

Explore BrainMass

    Electrostatic Force Calculations

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Please show all work and diagrams plus equations used to solve problem. Thanks!

    1) Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters. A third identical conducting sphere C is uncharged. SPhere C is first touched to A, then to B, and finally removed. As a result, the electrostatic force between a AND B, WHICH WAS ORIGINALLY F, BECOMES.

    2) Two particles have charges Q and -Q(equal magnitude and oposite sign). For a net force of zero to be exerted on a third charge it must be placed:
    (e is answer, but why???)

    a) midway between Q and -Q
    b) on the perpendicular bisector of the line joining Q and -Q, but not on that line itself.
    c) on the line joing Q and -Q, to the side Q opposite -Q.
    d) on the line joinging Q and -Q, to the side of -Q opposite Q.
    e) none of above(there is no place)

    © BrainMass Inc. brainmass.com March 4, 2021, 6:24 pm ad1c9bdddf
    https://brainmass.com/physics/charge/electrostatic-force-calculations-43446

    Solution Preview

    1) Since the distance between A and B is much larger than their eiameters, both conductors can be treated as point charges. When ...

    Solution Summary

    The solution provides step-by-step solutions with diagrams for questions related to elestrostatic force between conducting spheres and the net force between two oppositely charged particles.

    $2.49

    ADVERTISEMENT