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# Ideal gas problem involving heat, entropy, and work

See attached file.

#### Solution Preview

Note that in this problem the total volume stays constant and that the pressure in both sides is always equal. Let's calculate the number of helium atoms, the number of N_{2} atoms and the initial volume of the helium.

The atomic mass of helium is 4.002602u. This means that 0.1 kg corresponds to
1.50456*10^(25) helium atoms.

The initial volume then follows from the ideal gas law:

P_{initial}V_{He, initial} = N_{He} kT_{initial}

Inserting P_{initial} = 95*10^(3)Pa, T_{initial}= 293.15 K gives:

V_{He, initial} = 0.641 m^3

The initial volume of the N_{2} is 0.2 m^3, so we always have that:

V_{He} + V_{N_{2}} = 0.841 m^3

Using the ideal gas law we can also calculate the number of N_{2} molecules:

N_{N_{2}} = 4.6944*10^(24)

In the problem it is given that the ...

#### Solution Summary

The solution assists with solving the ideal gas problem involving heat, entropy and work.

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