Explore BrainMass

The Hydrogen Atom and the Radial Angular Momentum

Hydrogen atom
The radial probability density for an electron is r2R2(r). That means that the probability of finding an electron at a certain radius r within a radial thickness dr is dr* r2R2(r) for an infinitely thin shell and approximately r* r2avg R2(ravg) for a shell of finite thickness r.
The quantity ravg is some average radius within the shell...

(a) Estimate the probability that an electron in the n=1,l=0 state will be found in the region from r=0m to r= 10-15m.

(b) Repeat the calculation for n=2, l=1.

(c) Compare the two results, explain their difference, and explain the relevance of 10-15m distance from the center of the atom.

(d) Consider the state n=2, l=0 in hydrogen. What are the values of r for which the probability density is zero?
Sketch the probability density as a function of r for this state.

© BrainMass Inc. brainmass.com August 17, 2018, 5:05 am ad1c9bdddf

Solution Summary

The solution examines a hydrogen atom and the radial angular momentum. The probability that an electron in the n=1 and I=0 state will be found in the region from r=0m to r=10-15m is determined.